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24x^2+27x-17=0
a = 24; b = 27; c = -17;
Δ = b2-4ac
Δ = 272-4·24·(-17)
Δ = 2361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{2361}}{2*24}=\frac{-27-\sqrt{2361}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{2361}}{2*24}=\frac{-27+\sqrt{2361}}{48} $
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